(ii) (-5, -1) (3, -5) (5, 2)
हल – माना
A(-5, -1)
B(3, -5)
C(5, 2)
यहाँ
x1 = -5, y1 =
-1
x2 = 3, y2 =
-5
x3 = 5, y3 =
2
∴ Δ ABC का क्षेत्रफल
= ½ [x1(y2 – y3)
+ x2(y3 – y1) + x3(y1 – y2)]
= ½ [ -5(-5 – 2) + 3(2 + 1) + 5(-1 + 5)]
= ½ [ -5(-7) + 3(3) + 5(4)]
= ½ [ 35 + 9 + 20]
= ½ [ 64 ]
= 32 वर्ग इकाई