(ii) (-5, -1) (3, -5) (5, 2)

हल – माना
A(-5, -1)
B(3, -5)
C(5, 2)
यहाँ
x1 = -5,   y1 = -1
x2 = 3,   y2 = -5
x3 = 5,   y3 = 2

Δ ABC का क्षेत्रफल 
= ½ [x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)]
= ½ [ -5(-5 – 2) + 3(2 + 1) + 5(-1 + 5)]
= ½ [ -5(-7) + 3(3) + 5(4)]
= ½ [ 35 + 9 + 20]
= ½ [ 64 ]

= 32 वर्ग इकाई