(ii) (8, 1) (K, -4) (2, -5)
हल – माना
A(8, 1)
B(k, -4)
C(2, -5)
x1 = 8, y1 =
1
x2 = K, y2 =
-4
x3 = 2, y3 =
-5
∵
A, B और
C बिंदु संरेखीय है |
∴ Δ ABC का क्षेत्रफल = 0
½ [x1(y2 – y3) + x2(y3
– y1) + x3(y1 – y2)] = 0
½ [ 8(-4 + 5) + K(-5 - 1) + 2(1 + 4)] = 0
½ [ 8(1) + K(-6) + 2(5)] = 0
½ [ 8 – 6K + 10 ] = 0
½ [ 18 – 6K ] = 0
18 – 6K = 0
6K = 18
K = 18/6
K = 3
यही K का अभीष्ट मान है ।